the-master-schedule-for-parent-product-m-is-as-follows

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5.
The master schedule for parent
product M is as follows:

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

1.

2.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

3.

Week

Gross Requirements

1

3400

2

4200

3

5200

4

6300

5

7500

6

3100

7

4600

8

5400

9

6600

10

7800

4.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

5.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

The policy
is to carry no stock on-hand for m1, which is a subassembly
of M. Develop the planned-order release schedule for m1,
assuming a lot-for-lot sizing policy and lead time LT = one week.

6.
Use the information in Problem 5 to
address the decision of the MRP manager who wants to try 2-period ordering. She
requests that you compare your lot-for-lot plan with the 2-period plan. Also,
she asks, “Would it help to have some SOH”? Make the comparison and
answer the question.

9. Develop
the lot-for-lot ordering scenario for DVR-alpha part Q, using Table 15-5 in the
text and the product-structure tree in Figure 15-12. Note: Q appears more than
once in the product-structure tree. Also, observe the number of units of Q that
are required for each unit of X and for each unit of B. The lead times for both
X and B are zero because they can be assembled immediately. The lead time for Q
is one week. Part Q has no other parents or end-items than DVR-alpha.

In addition to providing the quantitative ordering
instructions, evaluate the performance of the ordering system.

Hint: Include in the planned-order release chart
levels 0, 1, and 2.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

Table 15-5 Master
DVR Schedule—Alpha and Beta Models

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image005.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_600px.gif”>

Week

Net requirements

1

2

3

4

5

6

7

8

9

10

Alpha model

60

80

40

Beta model

50

20

60

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image005.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_600px.gif”>

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

15-12

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image006.gif” alt=”Description: http://www.atomicdog.com/mybackpack/titles/ms-274-2/images/fig15-12.gif”>

1.
The matrix of total costs per day
for jobs 1, 2, and 3—if assigned at facilities A, B, and C of the Rivet and
Nail Factory—is

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

2.

3.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

4.

Facilities

A

B

C

Jobs

1

$1,000

$900

$1,200

2

800

700

900

3

1,500

1,800

2,000

5.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

6.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

What
relatively permanent assignments will minimize total costs per day?

2.
The matrix of costs per part
for jobs 4, 5, and 6—if assigned at facilities A, B, and C of the Rivet and
Nail Factory—is

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

1.

2.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

3.

Facilities

A

B

C

Jobs

4

$0.10

$0.19

$0.12

5

0.16

0.14

0.18

6

0.30

0.36

0.40

4.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

5.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

The jobs
are all of the same size (5,000) and duration. What relatively permanent
assignments will minimize total costs?

3.
The matrix of costs per part for
jobs 7, 8, and 9 if assigned at facilities A, B, and C of the Rivet and Nail
Factory is described by the matrix:

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

4.

5.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

6.

Facilities

A

B

C

Jobs

7

$0.10

0.09

$0.12

8

0.08

0.07

0.09

9

0.30

0.36

0.40

7.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

8.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

The jobs
are all of the same size (5,000 units) and duration. What relatively permanent
assignments will minimize total costs?

12.
The Door Knob Company has four
orders on hand, and each must be processed in the sequential order:

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

First: Department A—press shop

Second: Department B—plating and finishing

The following table lists the number of days required for each job in each
department. For example, job IV requires one day in the press shop and one day
in the finishing department.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

1.

2.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

3.

Job I

Job II

Job III

Job IV

Department A

8

6

5

1

Department B

8

3

4

1

4.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

5.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

Assume
that no other work is being done by the departments and that “no
passing” of jobs is allowed.Use a Gantt sequencing chart (see Figure 16-7)
to show the best-work schedule. (Best-work schedule means minimum time to
finish all four jobs.)

Figure 16-7 Gantt
Sequencing Chart for n× 2 Problem Where n = 5 Persons Being
Processed by m = 2 Facilities

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image007.gif” alt=”Description: http://www.atomicdog.com/mybackpack/titles/ms-274-2/images/fig16-7.gif”>

3. Line efficiency (A)) is a measure used to assess
line balance. It is given by Equation 17-6. Determine line efficiency for The
Photo Lab where n = 4, C = 1.5 minutes, and total work content is
4.8.

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

Equation 17-6

L = TWC/nC = Siti
where and i = all operations

4. Determine line efficiency (described in Problem
3) and relate it to the balance delay measure (given in Equation 17-4) for the
following conditions: Total work content is 3 hours; there are 180 stations
operating with a cycle time of one minute. Compare the results and meanings of d
and A .

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image001.gif” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/1x17_blank.gif”>

Equation 17 – 4

d = 100(nC–Siti) ÷nC

For The Photo Lab, what happens if tmax
can be reduced from 1.0 to 0.7 by improving the technology of the film
development step i = 6? Refer to Figure 17-2 and Tables 17-2 and 17-3.

Figure
17-2

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image008.gif” alt=”Description: http://www.atomicdog.com/mybackpack/titles/ms-274-2/images/fig17-2.gif”>

Table 17-2
Operation Times for The Photo Lab

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

Operation (i)

Operation Time (ti)
in Minutes

1

0.4

2

0.5

3

0.6

4

0.7

5

0.5

6

1.0 = tmax

7

0.6

8

0.1

9

0.4

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

Note: tmax
= 1.0 minute is the longest operation time.

Table 17-3 The
Photo Lab’s Processing Times

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

Operation (i)

Operation Time (ti)
in Minutes

1

0.4

2

0.5

3

0.6

4

0.7

5

0.5

6

1.0 = tmax

7

0.6

8

0.1

9

0.4

TWC

4.8 = Siti

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image003.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_450px.gif”>

Note: TWC =
total work content = Siti = 4.8 minutes.

6. Using the information in Problem 5, what occurs
if tmax is reduced from 1.0 to 0.6 by installing two photo
developing units in parallel for operation (6)? Develop a table similar to
Table 17-4.

Table 17-4 The Photo
Lab’s Chart of Possible Cycle Times, C, Also Hourly Output Rates, O
= T/C
, for Number of Stations, n

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image005.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_600px.gif”>

n

C = Siti/n in Minutes

O = T/C = 60/C Orders/Hour

Total Idle Time in Minutes

1

4.8

12.5

0

2

2.4

25.0

0

3

1.6

37.5

0

4

1.2

50.0

0

*5

0.96

62.5

0

*6

0.80

75.0

0

*7

0.69

87.5

0

*8

0.60

100.0

0

*9

0.53

112.5

0

The master schedule for parent product M is as follows.0/msohtmlclip1/01/clip_image005.jpg” alt=”Description: http://www.atomicdog.com/mybackpack/styles/images/table_bar_600px.gif”>

Note: (* =
infeasible)

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